Benjamin, Utah

From Wikipedia, the free encyclopedia

Benjamin is a census-designated place (CDP) in Utah County, Utah, United States. The population was 1,029 at the 2000 census.

[edit] Geography

Benjamin is located at 40°5′30″N, 111°43′22″W (40.091710, -111.722749)^GR1.

According to the United States Census Bureau, the CDP has a total area of 32.0 km² (12.4 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 1,029 people, 299 households, and 269 families residing in the CDP. The population density was 32.2/km² (83.3/mi²). There were 310 housing units at an average density of 9.7/km² (25.1/mi²). The racial makeup of the CDP was 98.64% White, 0.49% Native American, 0.19% Pacific Islander, 0.39% from other races, and 0.29% from two or more races. Hispanic or Latino of any race were 1.46% of the population.

There were 299 households out of which 45.8% had children under the age of 18 living with them, 81.3% were married couples living together, 7.0% had a female householder with no husband present, and 9.7% were non-families. 9.0% of all households were made up of individuals and 7.0% had someone living alone who was 65 years of age or older. The average household size was 3.44 and the average family size was 3.67.

In the CDP the population was spread out with 33.3% under the age of 18, 10.8% from 18 to 24, 24.2% from 25 to 44, 21.3% from 45 to 64, and 10.4% who were 65 years of age or older. The median age was 30 years. For every 100 females there were 104.6 males. For every 100 females age 18 and over, there were 102.4 males.

The median income for a household in the CDP was $46,458, and the median income for a family was $55,238. Males had a median income of $34,643 versus $21,151 for females. The per capita income for the CDP was $18,569. None of the families and 2.2% of the population were living below the poverty line, including no under eighteens and 9.2% of those over 64.