1959 NBA Playoffs
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The 1959 NBA Playoffs was the postseason tournament of the National Basketball Association's 1958-1959 season. The tournament concluded with the Eastern Conference champion Boston Celtics defeating the Western Conference champion Minneapolis Lakers, four games to none in the NBA Finals. It was the Celtics' second NBA championship.
This was the first NBA Finals matchup between the Lakers and Celtics; as of 2006 the franchises have met in the championship series 11 times. Boston won the first nine NBA Finals series of the rivalry, spanning three decades-- the 1950s, 1960s and 1980s-- before the Lakers finally defeated the Celtics for the title in 1985 and again in 1987. See also: Lakers-Celtics rivalry
This was also the only Celtics/Lakers NBA Finals series that would take place while the latter team was based in Minneapolis. Indeed, the Lakers would only remain in Minneapolis one more year before moving to their current home of Los Angeles.
| Conference Semifinals | Conference Finals | NBA Finals | |||||||||||
| 1 | St. Louis | 2 | |||||||||||
| Western Conference | |||||||||||||
| 2 | Minneapolis | 4 | |||||||||||
| 3 | Detroit | 1 | |||||||||||
| 2 | Minneapolis | 2 | |||||||||||
| W2 | Minneapolis | 0 | |||||||||||
| E1 | Boston | 4 | |||||||||||
| 1 | Boston | 4 | |||||||||||
| Eastern Conference | |||||||||||||
| 3 | Syracuse | 3 | |||||||||||
| 3 | Syracuse | 2 | |||||||||||
| 2 | New York | 0 | |||||||||||
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