Bradshaw, McDowell County, West Virginia

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Bradshaw is a town in McDowell County, West Virginia, USA. The population was 289 at the 2000 census. Bradshaw was incorporated in December 1979 and is named for a man who settled at the mouth of Bradshaw Creek in about 1840. His gravesite overlooks the town.

[edit] Geography

Bradshaw is located at 37°21′6″N, 81°47′57″W (37.351676, -81.799086)^GR1.

According to the United States Census Bureau, the town has a total area of 2.1 km² (0.8 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 289 people, 135 households, and 83 families residing in the town. The population density was 139.5/km² (362.8/mi²). There were 174 housing units at an average density of 84.0/km² (218.4/mi²). The racial makeup of the town was 99.65% White, and 0.35% from two or more races.

There were 135 households out of which 22.2% had children under the age of 18 living with them, 45.2% were married couples living together, 13.3% had a female householder with no husband present, and 38.5% were non-families. 36.3% of all households were made up of individuals and 14.1% had someone living alone who was 65 years of age or older. The average household size was 2.14 and the average family size was 2.77.

In the town the population was spread out with 20.8% under the age of 18, 8.3% from 18 to 24, 27.7% from 25 to 44, 28.4% from 45 to 64, and 14.9% who were 65 years of age or older. The median age was 41 years. For every 100 females there were 82.9 males. For every 100 females age 18 and over, there were 80.3 males.

The median income for a household in the town was $12,083, and the median income for a family was $14,750. Males had a median income of $35,625 versus $25,625 for females. The per capita income for the town was $9,458. About 43.7% of families and 54.9% of the population were below the poverty line, including 87.5% of those under the age of eighteen and 31.0% of those sixty five or over.