Paradise Hill, Oklahoma

From Wikipedia, the free encyclopedia

Paradise Hill is a town in Sequoyah County, Oklahoma, United States. It is part of the Fort Smith, Arkansas-Oklahoma Metropolitan Statistical Area. The population was 100 at the 2000 census.

[edit] Geography

Paradise Hill is located at 35°37′26″N, 95°4′14″W (35.624009, -95.070563)^GR1.

According to the United States Census Bureau, the town has a total area of 1.4 km² (0.5 mi²). 1.3 km² (0.5 mi²) of it is land and 1.89% is water.

[edit] Demographics

As of the census^GR2 of 2000, there were 100 people, 45 households, and 31 families residing in the town. The population density was 74.3/km² (191.6/mi²). There were 105 housing units at an average density of 78.0/km² (201.2/mi²). The racial makeup of the town was 76.00% White, 6.00% Native American, 1.00% from other races, and 17.00% from two or more races. Hispanic or Latino of any race were 4.00% of the population.

There were 45 households out of which 22.2% had children under the age of 18 living with them, 64.4% were married couples living together, 4.4% had a female householder with no husband present, and 31.1% were non-families. 28.9% of all households were made up of individuals and 11.1% had someone living alone who was 65 years of age or older. The average household size was 2.22 and the average family size was 2.74.

In the town the population was spread out with 17.0% under the age of 18, 5.0% from 18 to 24, 22.0% from 25 to 44, 27.0% from 45 to 64, and 29.0% who were 65 years of age or older. The median age was 48 years. For every 100 females there were 78.6 males. For every 100 females age 18 and over, there were 80.4 males.

The median income for a household in the town was $30,500, and the median income for a family was $38,125. Males had a median income of $43,333 versus $48,750 for females. The per capita income for the town was $22,835. There were 8.0% of families and 12.4% of the population living below the poverty line, including no under eighteens and 7.4% of those over 64.