Talk:Rhombus
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Changed picture caption as it is just one shape but turned on its side. 208.54.95.131 16:56, 16 Sep 2004 (UTC)
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[edit] Pointer
A rhombus is a parallelogram with all four sides the same length. --Aubrey Gotchlock Please create a pointer so that Rhomb can be found too. I do not know how to do this. :) --andy 80.129.124.140 17:17, 12 November 2005 (UTC)
[edit] "the different symmetry as the rhombus" ?
"The rhombus has the different symmetry as the rectangle..." It may be something mathy that I don't understand, but this seems really odd to me. Peter Delmonte 17:51, 23 November 2006 (UTC)
- Fixed. No mystery here — it was just someone being obtuse. That can't be right? 16:42, 13 February 2007 (UTC)
[edit] Confusing, bad english...
Things I don't like: the 'Two Definitions' heading and the bad English in the Properties section (a few stray "the"s for one). Intro could also use another wikilink or two. Shouldn't be hard to fix - I'm just too tired at the moment to do so. Tmandry 04:05, 19 December 2006 (UTC)
- I removed the "two definitions" statement. A square is certainly a rhombus mathematically (just as it is also a rectangle and a parallelogram). I realize that a square is not a "typical" rhombus and that we generally distinguish between a "square" and a "diamond" colloquially (although a baseball "diamond" is, for all intents and purposes, a square). However, a statement that a rhombus is NOT a square should be backed up by a citation. Paul D. Anderson 20:30, 21 December 2006 (UTC)
[edit] Posted proofs are inaccurate...
The first couple proofs posted (AC = AB + BC followed by BD = BC + CD = BC - AB), when based on the illustrated rhombus are clearly false. I'll summarize the inaccuracy of the first one (as the second's faults become readily apparent thereafter).
The rhombus pictured in the article is essentially made up of four right triangles. The right angles of these 4 triangles share the same vertex (in the middle of our rhombus, we'll call it X). AB and BC are both hypotenuses of X. AX and XC (our bisecting line) are both Catheti of Right Triangles. Based on the most fundamental Right Triangle Theorem (Pythagoras), the sum of two catheti, each from seperate Right Triangles, could never be equal to or greater than the sum of those two Right Triangles' hypotenuses.
No doubt, there's a more efficient way of demonstrating this, but it's been 14 years since I've even thought about a geometry proof, so it's a little clunky. —The preceding unsigned comment was added by K10wnsta (talk • contribs) 05:52, 9 March 2007 (UTC).
