Cedar Vale, Kansas

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Cedar Vale is a city in Chautauqua County, Kansas, United States. The population was 723 at the 2000 census.

[edit] Geography

Cedar Vale is located at 37°6′18″N, 96°30′3″W (37.104892, -96.500844)^GR1.

According to the United States Census Bureau, the city has a total area of 2.5 km² (0.9 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 723 people, 285 households, and 184 families residing in the city. The population density was 293.8/km² (758.8/mi²). There were 344 housing units at an average density of 139.8/km² (361.0/mi²). The racial makeup of the city was 92.67% White, 0.41% African American, 4.15% Native American, 1.11% from other races, and 1.66% from two or more races. Hispanic or Latino of any race were 2.07% of the population.

There were 285 households out of which 29.5% had children under the age of 18 living with them, 51.9% were married couples living together, 8.4% had a female householder with no husband present, and 35.1% were non-families. 33.3% of all households were made up of individuals and 22.5% had someone living alone who was 65 years of age or older. The average household size was 2.29 and the average family size was 2.91.

In the city the population was spread out with 24.6% under the age of 18, 4.6% from 18 to 24, 18.3% from 25 to 44, 23.5% from 45 to 64, and 29.0% who were 65 years of age or older. The median age was 47 years. For every 100 females there were 92.8 males. For every 100 females age 18 and over, there were 84.7 males.

The median income for a household in the city was $27,031, and the median income for a family was $33,889. Males had a median income of $24,167 versus $19,688 for females. The per capita income for the city was $14,410. About 11.1% of families and 14.7% of the population were below the poverty line, including 19.2% of those under age 18 and 14.5% of those age 65 or over.