User:Cryptanalysis
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a(aa) = b
(aa)loga = logb
(aa) = logb / loga
aloga = log(logb / loga)
aloga = log(logb) − log(loga)
a = (log(logb) − log(loga)) / loga
a(aa) = b
(aa)loga = logb
(aa) = logb / loga
a = (logb / loga)(1 / a)
(logb / loga)(1 / a) = (log(logb) − log(loga)) / loga
--Cryptanalysis 06:49, 16 February 2006 (UTC)
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