Algebraically closed group
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In mathematics, in the realm of group theory, a group is algebraically closed if any finite set of equations and inequations that "make sense" in
already have a solution in
. This idea will be made precise later in the article.
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[edit] Informal discussion
Suppose we wished to find an element of a group
satisfying the conditions (equations and inequations):
Then it is easy to see that this is impossible because the first two equations imply . In this case we say the set of conditions are inconsistent with
. (In fact this set of conditions are inconsistent with any group whatsoever.)
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Now suppose is the group with the multiplication table:
Then the conditions:
have a solution in , namely
.
However the conditions:
Do not have a solution in , as can easily be checked.
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However if we extend the group to the group
with multiplication table:
Then the condions have two solutions, namely and
.
Thus there are three possibilities regarding such conditions:
- The may be inconsistent with
and have no solution in any extension of
.
- They may have a solution in
.
- They may have no solution in
but nevertheless have a solution in some extension
of
.
It is reasonable to ask whether there are any groups such that whenever a set of conditions like these have a solution at all, they have a solution in
itself? The answer turns out to be "yes", and we call such groups algebraically closed groups.
[edit] Formal definition of an algebraically closed group
We first need some preliminary ideas.
If is a group and
is the free group on countably many generators, then by a finite set of equations and inequations with coefficients in
we mean a pair of subsets
and
of
the free product of
and
.
This formalizes the notion of a set of equations and inequations consisting of variables and elements
. The set
represents equations like:
The set represents inequations like
By a solution in to this finite set of equations and inequations, we mean a homomorphism
, such that
for all
and
for all
. Where
is the unique homomorphism
that equals
on
and is the identity on
.
This formalizes the idea of substituting elements of for the variables to get true identities and inidentities. In the example the substitutions
and
yield:
We say the finite set of equations and inequations is consistent with if we can solve them in a "bigger" group
. More formally:
The equations and inequations are consistent with if there is a group
and an embedding
such that the finite set of equations and inequations
and
has a solution in
. Where
is the unique homomorphism
that equals
on
and is the identity on
.
Now we formally define the group to be algebraically closed if every finite set of equations and inequations that has coefficients in
and is consistent with
has a solution in
.
[edit] Known Results
It is difficult to give concrete examples of algebraically closed groups as the following results indicate:
- Every countable group can be embedded in a countable algebraically closed group.
- Every algebraically closed group is simple.
- No algebraically closed group is finitely generated.
- An algebraically closed group cannot be recursively presented.
- A finitely generated group has solvable word problem if and only if it can embedded in every algebraically closed group.
The proofs of these results are, in general very complex. However a sketch the proof that a countable group can be embedded in an algebraically closed group follows.
First we embedd in a countable group
with the property that every finite set of equations with coefficients in
that is consistent in
has a solution in
as follows:
There are only countable many finite sets of equations and inequations with coefficients in . Fix an enumeration
of them. Define groups
inductively by:
Now let:
Now iterate this construction to get a sequence of groups and let:
Then is a countable group containing
. It is algebraically closed because any finite set of equations and inequations that is consistent with
must have coefficients in some
and so must have a solution in
.
[edit] References
- A. Macintyre: On algebraically closed groups, ann. of Math, 96, 53-97 (1972)
- B.H. Neumann: A note on algebraically closed groups. J. London Math. Soc. 27, 227-242 (1952)
- B.H. Neumann: The isomorphism problem for algebraically closed groups. In: Word Problems, pp 553-562. Amsterdam: North-Holland 1973
- W.R. Scott: Algebraically closed groups. Proc. Amer. Math. Soc. 2, 118-121 (1951)