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Factor theorem - Wikipedia, the free encyclopedia

Factor theorem

From Wikipedia, the free encyclopedia

In algebra, the factor theorem is a theorem for finding out the factors of a polynomial (an expression in which the terms are only added, subtracted or multiplied, e.g. x2 + 6x + 6). It is a special case of the polynomial remainder theorem.

[edit] An example

You wish to find the factors of

x3 + 7x2 + 8x + 2

To do this you would use trial and error finding the first factor. When the result is equal to 0, we know that we have a factor. Is (x − 1) a factor? To find out, substitute x = 1 into the polynomial above:

(13) + 7(12) + 8(1) + 2

This is equal to 18 not 0 so (x − 1) is not a factor of x3 + 7x2 + 8x + 2. So, we next try (x + 1) (substituting x = − 1 into the polynomial):

( − 13) + 7( − 12) + 8( − 1) + 2

This is equal to 0. Therefore x − ( − 1), which is to say x + 1, is a factor, and -1 is a root of x3 + 7x2 + 8x + 2

The next two roots can be found by algebraically dividing x3 + 7x2 + 8x + 2 by (x + 1) to get a quadratic, which can be solved directly, by the factor theorem or by the quadratic equation. (x^3 + 7x^2 + 8x + 2) \over (x + 1) = x2 + 6x + 2 and therefore (x + 1) and x2 + 6x + 2 are the factors of x3 + 7x2 + 8x + 2

[edit] Formal version

More formally, it states that for any polynomial

f(x),

for all values of a which satisfy

f(a) = 0,

(in which the value of a is substituted for x into the "y=" equation)

(xa) is a factor of f(x). Or, more concisely:

\frac{f(x)}{x-a} = q(x)

is a polynomial.

This indicates that any a for which f(-a) = 0, is a root of f(x). Double roots can be found by performing polynomial long division.

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