Hollandale, Wisconsin

From Wikipedia, the free encyclopedia

Hollandale is a village in Iowa County, Wisconsin, United States. The population was 283 at the 2000 census.

[edit] Geography

Hollandale is located at 42°52′34″N, 89°56′10″W (42.876139, -89.936023)^GR1.

According to the United States Census Bureau, the village has a total area of 1.8 km² (0.7 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 283 people, 121 households, and 75 families residing in the village. The population density was 158.4/km² (409.4/mi²). There were 128 housing units at an average density of 71.6/km² (185.2/mi²). The racial makeup of the village was 99.29% White, 0.71% from other races. Hispanic or Latino of any race were 0.35% of the population.

There were 121 households out of which 30.6% had children under the age of 18 living with them, 51.2% were married couples living together, 5.0% had a female householder with no husband present, and 38.0% were non-families. 32.2% of all households were made up of individuals and 21.5% had someone living alone who was 65 years of age or older. The average household size was 2.34 and the average family size was 2.99.

In the village the population was spread out with 22.6% under the age of 18, 5.7% from 18 to 24, 29.3% from 25 to 44, 23.0% from 45 to 64, and 19.4% who were 65 years of age or older. The median age was 40 years. For every 100 females there were 100.7 males. For every 100 females age 18 and over, there were 97.3 males.

The median income for a household in the village was $35,938, and the median income for a family was $50,139. Males had a median income of $34,167 versus $23,036 for females. The per capita income for the village was $21,141. About 2.9% of families and 3.5% of the population were below the poverty line, including none of those under the age of eighteen and 5.8% of those sixty five or over.