User:Pfafrich/Blahtex ^\sqrt bugs

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User:Pfafrich/Blahtex en.wikipedia fixup

This page is part a set of pages devoted to fixing latex bugs in the english wikipedia so that they will be compatable with the meta:Blahtex MathML project.

Below are pages which contain x^\sqrt',x^\acute etc. Each occurence x^\sqrt{a} should be replaced by x^{\sqrt{a}} and when fixed the pages should be moved to the done section. Feel free to fix as necessary.

The combinations affected are

x^\overline{y}
x^\left(y\right)
x^\acute{n}
x^\hat{n}
x^\mbox{n}
x^\sqrt{n}
x^\ldots
x^\overline{y}

for i in acute hat ldots left mbox overline sqrt underline ; do 
grep "\\^\\\\$i" eqnsJan06.txt >> raise.txt
done

[edit] Done

[edit] Undone

Asymptotic expansion $\zeta(s) \sim \sum_{n=1}^{N-1}n^{-s} + \frac{N^{1-s}}{s-1} + N^{-s} \sum_{m=1}^\infty \frac{B_{2m} s^\overline{2m-1}}{(2m)! N^{2m-1}}$
Asymptotic expansion $s^\overline{2m-1}$
Band gap $e^\left(\frac{-E_g}{kT}\right)$
Coupled cluster $\vert{\Psi}\rangle = e^\hat{T} \vert{\Phi_0}\rangle$
Difference quotient $=\frac{\sum_{I=0}^{\acute{N}}{-1\choose I}{\acute{N}\choose I}F(P_\acute{n}-I\Delta_1P)}{\Delta_1P^\acute{n}};\,\!$
Difference quotient $=\frac{\sum_{I=0}^{\acute{N}}{-1\choose\acute{N}-I}{\acute{N}\choose I}F(P_0+I\Delta_1P)}{\Delta_1P^\acute{n}};\,\!$
Difference quotient $\Delta^\acute{n}F(P_0)\,\!$
Difference quotient $\frac{D^\acute{n}F(P_0)}{DP^\acute{n}}\,\!$
Difference quotient $\frac{\Delta^\acute{n}F(P_0)}{\Delta_1P^\acute{n}}\,\!$

Difference quotient $\frac{\nabla^\acute{n}F(P_\acute{n})}{\Delta_1P^\acute{n}}\,\!$
Difference quotient $\frac{d^\acute{n}F(P_0)}{dP^\acute{n}}\,\!$
[[Gelfond<E2><80><93>Schneider constant]] $2^\sqrt{2}=2.6651441...$
[[Gelfond<E2><80><93>Schneider constant]] $\sqrt{2}^\sqrt{2}=1.6325269...$
Googol $10 googol$
Googolplex $10 10,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000$
Googolplex $10 googol$
Irrational number $\pi^\sqrt{2}$
Limit ordinal $\omega^3, \omega^4, \ldots, \omega^\omega, \omega^{\omega^\omega}, \ldots, \epsilon_0 = \omega^{\omega^{\omega^\ldots}}, \ldots$
Nonconstructive proof $\left (\sqrt{2}^\sqrt{2}\right )^\sqrt{2} = \sqrt{2}^{(\sqrt{2} \cdot \sqrt{2})} = \sqrt{2}^2 = 2$
Nonconstructive proof $\sqrt{2}^\sqrt{2}$
Nonconstructive proof $q = \sqrt{2}^\sqrt{2}$
Proof of Bertrand's postulate $(2n)^\sqrt{2n}$
Proof of Bertrand's postulate $\frac {4^n} {2n+1} \le (2n)^\sqrt{2n} 4^{\frac {2n} {3}}$
Proof of Bertrand's postulate $\frac {4^n}{2n+1} \le {2n \choose n} \le (2n)^\sqrt{2n} \prod_{p \in \mathbb{P} }^{\frac {2n} {3}} p = (2n)^\sqrt{2n} e^{\theta(\frac {2n} {3})}$
Rigid rotor $P_l^\left |m \right | (\cos \theta)$
Rigid rotor $Y_{l,m}(\theta,\phi) = \left [ \sqrt{ {(2l+1) \over 2} {( l - \left |m \right |)! \over (l + \left |m \right |)!} } P_l^\left |m \right | (\cos \theta) \right ] \left [ \sqrt {{1 \over 2\pi}} \exp (im\phi) \right ]$
Schwarzschild coordinates $d\sigma^\hat{m} = -{\omega^\hat{m}}_\hat{n} \, \wedge \sigma^\hat{n}$
Schwarzschild coordinates ${\Omega^\hat{m}}_\hat{n} = d{\omega^\hat{m}}_\hat{n} \wedge \sigma^\hat{n} - {\omega^\hat{m}}_\hat{\ell} \wedge {\omega^\hat{\ell}}_\hat{n}$
Schwarzschild coordinates ${\Omega^\hat{m}}_\hat{n} = {R^\hat{m}}_{\hat{n}|\hat{i}\hat{j}|} \, \sigma^\hat{i} \wedge \sigma^\hat{j}$
Schwarzschild coordinates ${\omega^\hat{m}}_\hat{n}$
Space charge $i = (1-\tilde{r})A_0T^2e^\left(\frac{-e\phi}{kT}\right)$
User:Bkell/Sandbox ${}^\underline{355}_{113}$
User:Neocapitalist $(\sqrt{2}^\sqrt{2})^\sqrt{2}=\sqrt{2}^2=2$
User:Neocapitalist $\sqrt{2}^\sqrt{2}$
User:Neocapitalist $a=(\sqrt{2}^\sqrt{2})$
User:Neocapitalist $k^n=\sqrt{2}^\sqrt{2}$
User:Pjacobi/Scratchpad
User:Stendhalconques $\zeta(s) \sim \sum_{n=1}^{N-1}n^{-s} + \frac{N^{1-s}}{s-1} + N^{-s} \sum_{m=1}^\infty \frac{B_{2m} s^\overline{2m-1}}{(2m)! N^{2m-1}}$
User:Stendhalconques $s^\overline{2m-1}$

[edit] Update

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No, "x^\frac{a}{b}" is perfectly okay! On both blahtex and regular LaTeX!

Even "x^\frac a b" is fine.

The reason: "\frac" is a macro in LaTeX, and "x^\frac a b" gets expanded as "x^{a \over b}" (well maybe something more complicated, but you get the idea).

Blahtex knows this about "\frac".

So leave this page alone and go onto the next one!!! Dmharvey 03:55, 11 February 2006 (UTC)

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Retrieved from "http://en.wikipedia.org../../../p/f/a/User%7EPfafrich_Blahtex_%5E_sqrt_bugs_f4cc.html"

User:Pfafrich/Blahtex ^\sqrt bugs

From Wikipedia, the free encyclopedia

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[edit] Undone

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