Ferdinand, Idaho

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Ferdinand is a city in Idaho County, Idaho, United States. The population was 145 at the 2000 census.

[edit] Geography

Ferdinand is located at 46°9′10″N, 116°23′26″W (46.152701, -116.390438)^GR1.

According to the United States Census Bureau, the city has a total area of 0.4 km² (0.1 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 145 people, 60 households, and 40 families residing in the city. The population density was 399.9/km² (1,027.1/mi²). There were 67 housing units at an average density of 184.8/km² (474.6/mi²). The racial makeup of the city was 98.62% White, 0.69% Native American, and 0.69% from two or more races.

There were 60 households out of which 36.7% had children under the age of 18 living with them, 55.0% were married couples living together, 6.7% had a female householder with no husband present, and 31.7% were non-families. 31.7% of all households were made up of individuals and 18.3% had someone living alone who was 65 years of age or older. The average household size was 2.42 and the average family size was 3.00.

In the city the population was spread out with 30.3% under the age of 18, 6.9% from 18 to 24, 25.5% from 25 to 44, 21.4% from 45 to 64, and 15.9% who were 65 years of age or older. The median age was 35 years. For every 100 females there were 93.3 males. For every 100 females age 18 and over, there were 102.0 males.

The median income for a household in the city was $26,250, and the median income for a family was $35,625. Males had a median income of $25,750 versus $22,917 for females. The per capita income for the city was $13,513. There were 2.9% of families and 9.9% of the population living below the poverty line, including 20.0% of under eighteens and 11.8% of those over 64.