Franklin, Alabama

From Wikipedia, the free encyclopedia

Franklin is a town in Macon County, Alabama, United States. At the 2000 census the population was 149.

[edit] Geography

Franklin is located at 32°27′19″N, 85°48′10″W (32.455388, -85.802884)^GR1.

According to the U.S. Census Bureau, the town has a total area of 8.7 km² (3.3 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 149 people, 64 households, and 48 families residing in the town. The population density was 17.2/km² (44.6/mi²). There were 77 housing units at an average density of 8.9/km² (23.0/mi²). The racial makeup of the town was 43.62% White and 56.38% Black or African American. 0.67% of the population were Hispanic or Latino of any race.

There were 64 households out of which 28.1% had children under the age of 18 living with them, 51.6% were married couples living together, 15.6% had a female householder with no husband present, and 25.0% were non-families. 21.9% of all households were made up of individuals and 10.9% had someone living alone who was 65 years of age or older. The average household size was 2.33 and the average family size was 2.69.

In the town the population was spread out with 20.1% under the age of 18, 10.7% from 18 to 24, 18.1% from 25 to 44, 33.6% from 45 to 64, and 17.4% who were 65 years of age or older. The median age was 47 years. For every 100 females there were 96.1 males. For every 100 females age 18 and over, there were 88.9 males.

The median income for a household in the town was $35,000, and the median income for a family was $42,188. Males had a median income of $32,917 versus $29,821 for females. The per capita income for the town was $34,572. There were none of the families and 4.9% of the population living below the poverty line, including no under eighteens and 9.7% of those over 64.