Hayward (town), Wisconsin
From Wikipedia, the free encyclopedia
Hayward is a town in Sawyer County, Wisconsin, United States. The population was 3,279 at the 2000 census. The town is located near the City of Hayward.
[edit] Geography
According to the United States Census Bureau, the town has a total area of 165.8 km² (64.0 mi²). 148.7 km² (57.4 mi²) of it is land and 17.0 km² (6.6 mi²) of it (10.27%) is water.
[edit] Demographics
As of the census2 of 2000, there were 3,279 people, 1,219 households, and 898 families residing in the town. The population density was 22.0/km² (57.1/mi²). There were 1,841 housing units at an average density of 12.4/km² (32.1/mi²). The racial makeup of the town was 74.53% White, 0.09% Black or African American, 23.54% Native American, 0.40% Asian, 0.06% Pacific Islander, 0.18% from other races, and 1.19% from two or more races. 0.64% of the population were Hispanic or Latino of any race.
There were 1,219 households out of which 34.4% had children under the age of 18 living with them, 56.3% were married couples living together, 12.5% had a female householder with no husband present, and 26.3% were non-families. 21.6% of all households were made up of individuals and 9.2% had someone living alone who was 65 years of age or older. The average household size was 2.63 and the average family size was 3.05.
In the town the population was spread out with 28.5% under the age of 18, 5.9% from 18 to 24, 25.4% from 25 to 44, 24.0% from 45 to 64, and 16.2% who were 65 years of age or older. The median age was 39 years. For every 100 females there were 97.9 males. For every 100 females age 18 and over, there were 94.7 males.
The median income for a household in the town was $36,895, and the median income for a family was $43,300. Males had a median income of $30,972 versus $21,534 for females. The per capita income for the town was $17,382. About 12.6% of families and 13.6% of the population were below the poverty line, including 18.2% of those under age 18 and 13.4% of those age 65 or over.
