Howard, Kansas

From Wikipedia, the free encyclopedia

Howard is a city in Elk County, Kansas, United States. The population was 808 at the 2000 census. It is the county seat of Elk County^GR6.

[edit] Geography

Howard is located at 37°28′7″N, 96°15′47″W (37.468517, -96.263014)^GR1.

According to the United States Census Bureau, the city has a total area of 1.8 km² (0.7 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 808 people, 350 households, and 215 families residing in the city. The population density was 445.7/km² (1,154.6/mi²). There were 452 housing units at an average density of 249.3/km² (645.9/mi²). The racial makeup of the city was 94.93% White, 0.25% African American, 1.24% Native American, 0.62% Asian, 0.62% from other races, and 2.35% from two or more races. Hispanic or Latino of any race were 1.98% of the population.

There were 350 households out of which 24.0% had children under the age of 18 living with them, 51.7% were married couples living together, 6.3% had a female householder with no husband present, and 38.3% were non-families. 37.4% of all households were made up of individuals and 23.7% had someone living alone who was 65 years of age or older. The average household size was 2.16 and the average family size was 2.83.

In the city the population was spread out with 22.4% under the age of 18, 5.4% from 18 to 24, 19.2% from 25 to 44, 22.8% from 45 to 64, and 30.2% who were 65 years of age or older. The median age was 47 years. For every 100 females there were 81.6 males. For every 100 females age 18 and over, there were 78.6 males.

The median income for a household in the city was $25,822, and the median income for a family was $28,365. Males had a median income of $24,886 versus $16,354 for females. The per capita income for the city was $15,441. About 11.9% of families and 14.5% of the population were below the poverty line, including 17.2% of those under age 18 and 14.6% of those age 65 or over.