Talk:Hyperbolic trajectory
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Formula on the page is wrong.
- Thank you for letting us know; I corrected the formula. 62.245.80.251 11:47, 20 March 2006 (UTC)
The first link in the External links section (http://www.cix.co.uk/~sjbradshaw/msc/traject.html) appears to be broken.Ugo 11:50, 6 November 2006 (UTC)
[edit] In English please?
Can someone explain what a hyperbolic trajectory is in slightly more layman's terms?
