Johnstown, Nebraska

From Wikipedia, the free encyclopedia

Johnstown is a village in Brown County, Nebraska, United States. The population was 53 at the 2000 census.

1 Geography
2 Demographics
3 Notable events
4 External links

[edit] Geography

Johnstown is located at 42°34′21″N, 100°3′25″W (42.572466, -100.057054)^GR1.

According to the United States Census Bureau, the village has a total area of 1.4 km² (0.5 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 53 people, 24 households, and 13 families residing in the village. The population density was 38.6/km² (100.8/mi²). There were 35 housing units at an average density of 25.5/km² (66.5/mi²). The racial makeup of the village was 92.45% White, 1.89% Asian, and 5.66% from two or more races.

There were 24 households out of which 16.7% had children under the age of 18 living with them, 54.2% were married couples living together, 4.2% had a female householder with no husband present, and 41.7% were non-families. 37.5% of all households were made up of individuals and 20.8% had someone living alone who was 65 years of age or older. The average household size was 2.21 and the average family size was 2.93.

In the village the population was spread out with 18.9% under the age of 18, 9.4% from 18 to 24, 17.0% from 25 to 44, 32.1% from 45 to 64, and 22.6% who were 65 years of age or older. The median age was 47 years. For every 100 females there were 96.3 males. For every 100 females age 18 and over, there were 95.5 males.

The median income for a household in the village was $20,625, and the median income for a family was $28,750. Males had a median income of $18,750 versus $8,750 for females. The per capita income for the village was $21,380. There were no families and 3.6% of the population living below the poverty line, including no under eighteens and 14.3% of those over 64.