Libertyville, Iowa

From Wikipedia, the free encyclopedia

Libertyville is a city in Jefferson County, Iowa, United States. The population was 325 at the 2000 census.

[edit] Geography

Libertyville is located at 40°57′28″N, 92°2′57″W (40.957911, -92.049085)^GR1.

According to the United States Census Bureau, the city has a total area of 1.3 km² (0.5 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 325 people, 138 households, and 85 families residing in the city. The population density was 256.1/km² (665.4/mi²). There were 143 housing units at an average density of 112.7/km² (292.8/mi²). The racial makeup of the city was 97.54% White, 0.31% African American, 0.31% Native American, 0.31% Asian, and 1.54% from two or more races. Hispanic or Latino of any race were 0.92% of the population.

There were 138 households out of which 29.7% had children under the age of 18 living with them, 55.1% were married couples living together, 5.1% had a female householder with no husband present, and 37.7% were non-families. 32.6% of all households were made up of individuals and 15.2% had someone living alone who was 65 years of age or older. The average household size was 2.36 and the average family size was 3.05.

In the city the population was spread out with 26.8% under the age of 18, 6.8% from 18 to 24, 31.7% from 25 to 44, 21.8% from 45 to 64, and 12.9% who were 65 years of age or older. The median age was 37 years. For every 100 females there were 91.2 males. For every 100 females age 18 and over, there were 84.5 males.

The median income for a household in the city was $31,071, and the median income for a family was $41,875. Males had a median income of $27,250 versus $17,656 for females. The per capita income for the city was $14,368. About 9.8% of families and 12.5% of the population were below the poverty line, including 16.1% of those under age 18 and none of those age 65 or over.