Markleville, Indiana

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Markleville from the air, looking west.

Markleville is a town in Madison County, Indiana, United States. It is part of the Anderson, Indiana Metropolitan Statistical Area. The population was 383 at the 2000 census.

[edit] Geography

Markleville is located at 39°58′46″N, 85°37′2″W (39.979501, -85.617273)^GR1.

According to the United States Census Bureau, the town has a total area of 1.1 km² (0.4 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 383 people, 141 households, and 111 families residing in the town. The population density was 360.7/km² (943.7/mi²). There were 149 housing units at an average density of 140.3/km² (367.1/mi²). The racial makeup of the town was 99.74% White, and 0.26% from two or more races.

There were 141 households out of which 31.2% had children under the age of 18 living with them, 67.4% were married couples living together, 8.5% had a female householder with no husband present, and 20.6% were non-families. 16.3% of all households were made up of individuals and 9.2% had someone living alone who was 65 years of age or older. The average household size was 2.72 and the average family size was 3.02.

In the town the population was spread out with 24.5% under the age of 18, 6.8% from 18 to 24, 28.7% from 25 to 44, 27.2% from 45 to 64, and 12.8% who were 65 years of age or older. The median age was 38 years. For every 100 females there were 96.4 males. For every 100 females age 18 and over, there were 105.0 males.

The median income for a household in the town was $48,438, and the median income for a family was $50,313. Males had a median income of $30,781 versus $22,981 for females. The per capita income for the town was $17,395. None of the families and 0.8% of the population were living below the poverty line, including no under eighteens and none of those over 64.