Talk:Method of moments (probability theory)
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Doesn't this result also require that X is uniquely determined by its moments? McKay 11:07, 14 June 2006 (UTC)
- You're right. I have now added that assumption. Michael Hardy 17:32, 14 June 2006 (UTC)
Next question is whether we have to say that each Xn has to have all its moments. Suppose that in fact only the first n moments of Xn exist. Then the k-th moments can still converge (using the usual convention that finite prefixes of sequences are ignored in deciding convergence) -- but is the theorem true in that case? 01:37, 15 June 2006 (UTC)
