Pickstown, South Dakota

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Pickstown is a town in Charles Mix County, South Dakota, United States. The population was 168 at the 2000 census.

1 Geography
2 Demographics
3 Services
4 Points of interest
5 External links

[edit] Geography

Pickstown is located at 43°3′59″N, 98°31′55″W (43.066418, -98.531991)^GR1.

According to the United States Census Bureau, the town has a total area of 1.7 km² (0.6 mi²), all land.

Pickstown has been assigned the ZIP code 57367 and the FIPS place code 49460.

[edit] Demographics

As of the census^GR2 of 2000, there were 168 people, 76 households, and 49 families residing in the town. The population density was 101.4/km² (260.7/mi²). There were 88 housing units at an average density of 53.1/km² (136.5/mi²). The racial makeup of the town was 85.12% White, 11.31% Native American, 0.60% Asian, and 2.98% from two or more races.

There were 76 households out of which 22.4% had children under the age of 18 living with them, 57.9% were married couples living together, 2.6% had a female householder with no husband present, and 35.5% were non-families. 26.3% of all households were made up of individuals and 6.6% had someone living alone who was 65 years of age or older. The average household size was 2.21 and the average family size was 2.69.

In the town the population was spread out with 19.6% under the age of 18, 3.6% from 18 to 24, 28.6% from 25 to 44, 28.0% from 45 to 64, and 20.2% who were 65 years of age or older. The median age was 44 years. For every 100 females there were 124.0 males. For every 100 females age 18 and over, there were 121.3 males.

The median income for a household in the town was $50,250, and the median income for a family was $55,250. Males had a median income of $39,375 versus $19,792 for females. The per capita income for the town was $20,755. None of the families and 1.1% of the population were living below the poverty line, including no under eighteens and 6.3% of those over 64.