Zapata Ranch, Texas

From Wikipedia, the free encyclopedia

Zapata Ranch is a census-designated place in Willacy County, Texas, United States. The population was 88 at the 2000 census.

1 Geography
2 Demographics
3 Education
4 External links

[edit] Geography

Zapata Ranch is located at 26°21′38″N, 97°49′15″W (26.360498, -97.820948)^GR1.

According to the United States Census Bureau, the CDP has a total area of 3.7 km² (1.4 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 88 people, 28 households, and 22 families residing in the CDP. The population density was 24.1/km² (62.5/mi²). There were 31 housing units at an average density of 8.5/km² (22.0/mi²). The racial makeup of the CDP was 77.27% White, 3.41% African American, 19.32% from other races. Hispanic or Latino of any race were 80.68% of the population.

There were 28 households out of which 39.3% had children under the age of 18 living with them, 46.4% were married couples living together, 17.9% had a female householder with no husband present, and 21.4% were non-families. 21.4% of all households were made up of individuals and 17.9% had someone living alone who was 65 years of age or older. The average household size was 3.14 and the average family size was 3.73.

In the CDP the population was spread out with 31.8% under the age of 18, 10.2% from 18 to 24, 28.4% from 25 to 44, 14.8% from 45 to 64, and 14.8% who were 65 years of age or older. The median age was 33 years. For every 100 females there were 100.0 males. For every 100 females age 18 and over, there were 114.3 males.

The median income for a household in the CDP was $14,444, and the median income for a family was $20,500. Males had a median income of $14,191 versus $9,417 for females. The per capita income for the CDP was $10,206. None of the population or families were below the poverty line.