Wausaukee (town), Wisconsin
From Wikipedia, the free encyclopedia
Wausaukee is a town in Marinette County, Wisconsin, United States. The population was 1,196 at the 2000 census. The Village of Wausaukee is located within the town.
[edit] Geography
According to the United States Census Bureau, the town has a total area of 200.6 km² (77.4 mi²). 196.1 km² (75.7 mi²) of it is land and 4.4 km² (1.7 mi²) of it (2.21%) is water.
[edit] Demographics
As of the census2 of 2000, there were 1,196 people, 469 households, and 354 families residing in the town. The population density was 6.1/km² (15.8/mi²). There were 1,036 housing units at an average density of 5.3/km² (13.7/mi²). The racial makeup of the town was 98.49% White, 0.08% Black or African American, 0.33% Native American, 0.33% Asian, 0.08% from other races, and 0.67% from two or more races. 0.42% of the population were Hispanic or Latino of any race.
There were 469 households out of which 30.1% had children under the age of 18 living with them, 65.9% were married couples living together, 6.4% had a female householder with no husband present, and 24.5% were non-families. 20.9% of all households were made up of individuals and 9.8% had someone living alone who was 65 years of age or older. The average household size was 2.55 and the average family size was 2.93.
In the town the population was spread out with 25.9% under the age of 18, 3.8% from 18 to 24, 23.3% from 25 to 44, 31.3% from 45 to 64, and 15.7% who were 65 years of age or older. The median age was 43 years. For every 100 females there were 101.7 males. For every 100 females age 18 and over, there were 105.1 males.
The median income for a household in the town was $35,530, and the median income for a family was $39,375. Males had a median income of $32,337 versus $20,476 for females. The per capita income for the town was $18,610. About 2.9% of families and 5.5% of the population were below the poverty line, including 2.2% of those under age 18 and 7.1% of those age 65 or over.
